nice C-puzzle
void fun(void)
{
/*Do something here so that the printf stmt in main function prints something other than 20 */
}
int main()
{
int i = 20;
fun();
printf("%d", i);
}
One Solution is...
void fun(void)
{
#define printf(a,b) printf("%d",10);
// we can also use
// #define fun() i=10
}
int main()
{
int i = 20;
fun();
printf("%d", i);
}
{
/*Do something here so that the printf stmt in main function prints something other than 20 */
}
int main()
{
int i = 20;
fun();
printf("%d", i);
}
One Solution is...
void fun(void)
{
#define printf(a,b) printf("%d",10);
// we can also use
// #define fun() i=10
}
int main()
{
int i = 20;
fun();
printf("%d", i);
}
posted by srividya at
8:31 PM
3 Comments:
1. We could print some thing else in fun() and the use exit.
void fun(){
printf("GG");exit(1);
}
2. Well since there is no \n or \t there no mater what you print 20follows.
void fun(){
printf("1233432");
}
result is 123343220 (which is !=20)
By
manjunath, at 9:30 AM
/*Do something here so that the main function prints something other than 20*/
we should make printf in main function to print other than 20. Not the other way.
By
srividya, at 9:40 PM
All the modifications should be made in fun()
Isn't that right?
I gave both of my answers inside fun method i suppose.
By
manjunath, at 7:45 PM
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